Assembly example: belt conveyor
A combined example for a belt conveyor: the same problem flows through four selection steps — tractive force, power, torque and coupling — using each step's standard formula.
How to use
- Enter the calculation conditions
Enter the dimensions, loads, speeds or operating conditions requested by the form.
- Run the calculation
The tool applies the formulas shown on this page to the entered values.
- Review the result
Review the resulting specification and checks, then verify them against the cited source, current standard and real operating conditions before use.
Core formula
Fe=M·g·(μ·cosβ+sinβ); F_peak=Fe+M·a; P=Fe·v/η; T_pulley=F_peak·Dp/2; T_motor=T_pulley/(N·η)
Example using default values
M=60 kg, v=30 m/min, Dp=150, N=20 → Fe≈20.6 N, P≈12 W, T≈0.34 N·m @1273 rpm
Source: Belt-conveyor principles (CEMA / maker literature); Oriental Motor Sizing; KTR/NBK (coupling).
Frequently asked questions
What makes up the conveyor tractive force?
In steady running it is friction (μ·M·g·cosβ) plus the gravity component on an incline (M·g·sinβ). At start-up add the acceleration force M·a. This is a lumped model; for long/heavy belts separate the tight/slack tensions per a standard (CEMA).
Size a conveyor motor by power or torque?
Both: power P=Fe·v/η sets the continuous motor size, while peak torque (including start-up) drives the gearbox and start capability. Conveyors typically use an integrated gearmotor.
What extra care for inclined conveyors?
You need a brake or anti-runback so the load cannot slide back on power loss; holding and braking torque must be checked separately. Steep inclines also need cleated/sidewall belts so the load does not slip.
MINATA — minatavn.com